What volume of 0.5 N NaOH neutralizes 6.3 g of oxalic acid crystals?
What volume of 0.5 N NaOH neutralizes 6.3 g of oxalic acid crystals?
Aditya Sharma , 5 Years ago
Grade 11
Inorganic Chemistry> What volume of 0.5 N NaOH neutralizes 6.3...
1 Answers
Arun
Last Activity: 5 Years ago
This question involves concept of volumetry
We can get the answer using the formula
N1V1=N2V2 ie. Principle of neutralization
Here
Oxalic acid is a dibasic acid as it can release two H+
Hence Molarity = (6.3 x 1000)/( 126 x 250) = 0.2
=> normality = 0.2 x 2 = 0.4
For req volume of NaOH
0.4 x 10 = 0.1 x V2
=> V2 = 40 ml
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