Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

What mass of NA2SO4. 7H2O contain exactly 6.022 *10^22 atoms of oxygen

What mass of NA2SO4. 7H2O contain exactly 6.022 *10^22 atoms of oxygen 

Grade:11

1 Answers

Arun
25763 Points
2 years ago
Dear Sachin
 
6.022* 10^22 * 1 molecues NA2SO4. 7H2O / 11 Oxygen atoms
 
 = 0.547 * 10^22 molecules NA2SO4. 7H2O 
 
Now
 
moles = 0.547 * 10^22 / 6.023 * 10^23 = 0.009 moles of NA2SO4. 7H2O 
 
hence mass  = 0.009 * (46+32+64+126) = 0.009 * 268 = 2.412 gm

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free