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Grade: 12th pass

                        

What is the Oxidation state of sulphur in thionic acid(h2s2o3)?Please explain it with the help of fundamental concept and with it's structure.

What is the Oxidation state of sulphur in thionic acid(h2s2o3)?Please explain it with the help of fundamental concept and with it's structure. 

2 years ago

Answers : (2)

Arun
25768 Points
							
Dear Ashish
 
I am trying to give goosd explanation.
Na2S2O3
Oxidation state of 'S' you do not know, ok
Oxidation state for sodium = 1, So, Two sodium gets (1+1)= 2
Your question is oxidation state for sulphur, So unknown, There are two sulphur atoms are there, we will write as 2x
Oxidation state for oxygen = -2.There are there are three oxygen atoms, So
                                              (-2*3)= -6
Just apply in the avove molecular fomula,
Na2S2O3
(2+2x-6) = 0
(2-6)+2x= 0
-4+2x= 0
x " means sulphur atom = 2, So
Osidation state of sulphur is "2"
2 years ago
Ritik kumar
16 Points
							
Oxidation state of sulpher is  +4 . Because S attached to other S with =bond lonely. and oxigen (with =bond),two OH gp attached with one of the S.so that one S has zero oxidn state and other has +4
 
2 years ago
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