what is oxidation state of S in S2O3. as there is electronegativity difference in both s shouldn’t it +6 and -2

Reason being the overall charge of the compound is -2
the oxidation state for Oxygen is -2 (Oxygen is just about always that way)
so -2 x 3 = -6
but as i said before the overall charge of the compound is -2 so we have to go from -6 to -2 so the Sulfur composes the positive charge to make up for the 4 units between -6 and -2
and we have two Sulfur's so 4= 2x
x= +2