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Vapour density of a volatile chloride of a metal is 95 and specific heat of metal is 0.13. The equivalent weight of metal is
Molecular weight of volatile chloride = 2*95 = 190Formula of chloride = MClxApproximate weight of M = 6.4/0.13= 49.23Let valency of M be x.Formula of MClx = 49.23 + x * 35.5= 190x = 140.77/35.5= 3.96 = 4Therefore, equivalents weight = 49.23/4 =12.3 Therefore equivalent weight = 49.23/4 = 12.3
Molecular weight of volatile chloride = 2*95
= 190
Formula of chloride = MClx
Approximate weight of M = 6.4/0.13
= 49.23
Let valency of M be x.
Formula of MClx = 49.23 + x * 35.5
x = 140.77/35.5
= 3.96 = 4
Therefore, equivalents weight = 49.23/4
=12.3
Therefore equivalent weight = 49.23/4 = 12.3
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