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Total no.of isomers for a square planar complex [M(F)(Cl)(SCN)(NO2)]

Total no.of isomers for a square planar complex [M(F)(Cl)(SCN)(NO2)]

Grade:12th pass

3 Answers

Arun
25750 Points
5 years ago
For any square planar complex of type MABCD,there are no optical isomers but only geometrical isomers.There will be a total of 3 isomers.The three isomers place A trans to C,A trans to B,and A trans to D.There won't be any chiral isomer because there is always a plane of symmetry present in the square planar complex.Hence,a total of 3 isomers.
Tanmay
15 Points
5 years ago
I'm the one who posed the question the answer is 12 not 3 
It's a mains question from jan.Hence Ur ans 3 is wrong              
Sanngesh
19 Points
5 years ago
We should see the linkage isomerism also. ONO and NO2 , CNS NCS So 3*4 ways will be there   .
                                      
 
 
We should include all isomerisms possi
 

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