To a 25 ml H 2 O 2 solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H 2 O 2 solution.

Question

Jitender Pal · Answer

Meq. Of H 2 O 2 = Meq. Of Na 2 S 2 O 3 w/17 * 1000 = 20 * 0.3 &there4; w = 0.102 g H 2 O 2 &rarr; H 2 O + 1/2 O 2 &there4; Volume of O 2 = 11200 *0.102/34 = 33.6 mL &there4; Volume strength = 33.6/25 = 1.344

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To a 25 ml H 2 O 2 solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H 2 O 2 solution.

To a 25 ml H₂O₂ solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H₂O₂ solution.

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To a 25 ml H 2 O 2 solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H 2 O 2 solution.

To a 25 ml H2O2 solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H2O2 solution.

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To a 25 ml H₂O₂ solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H₂O₂ solution.