MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
This is a question of chapter equilibrium. .. and i just want to know the formula used in it
2 months ago

Answers : (2)

Arun
22989 Points
							
Ka for acetic acid is 1.8 x 10-5.
Acetic acid, CH3COOH is a weak acid which ionizes partially and sodium acetate is a strong electrolyte which ionizes completely in the solution. Let x be the number of moles of acetic acid ionized.
Then, the concentrations of various species are:
CH3COOH (aq) + H2O [H3O+] = 3.6 x 10-6 mol L-1
[H3O+] = 1.8 x 10-5 x 0.02 / 0.1
1.8 x 10-5 = [H3O+] x 0.1 / 0.02
Ka for acetic acid is 1.8 x 10-5 (given)
[CH3COOH]
Ka = [H3O+] [CH3COO–]
Ionization constant, Ka is:
[CH3COOH] = 0.02 – x = 0.02 mol L-1
[CH3COO–] = 0.1 + x = 0.1 mol L-1
Now, x is very small in comparison to 0.1 so that
Concentration of acetic acid left unionized = 0.02 – x
Therefore, total [CH3COO–] = 0.1 + x
The concentration of acetate ion from sodium acetate = 0.1 M
Since sodium acetate is completely ionized,
Concentration of acetate ions from acetic acid = x
CH3COONa (aq) —————-> CH3COO– (aq) + Na+(aq)
CH3COO– (aq) + H3O+ (aq)
 
2 months ago
Vikas TU
9476 Points
							
Dear student 
There is no special formula used in this , The formula used gere is only , the Product side concentration / Reactant side concentration . 
Hope this clears your doubt . 
Good Luck 
2 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 54 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details