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The wavelength of the third line of balmer series for hydrogen atom is what?

The wavelength of the third line of balmer series for hydrogen atom is what?

Grade:12th pass

2 Answers

Vikas TU
14149 Points
4 years ago
Dear Student,
From Reydberg constant formulae:
1/lambda= (1/(2^2)- 1/(5^2))x109678 for every cm. 
lambda on solving= 4.34x10^(- 5) cm. 
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Bhavesh Tyagi
15 Points
2 years ago
Hello,
Here n1= 2  and n2= 5 
 Put this in formula,
            1/ Lambda = R (Z)² (1/n1² - 1/n2²) 
             Where R = 109678 cm-¹ and z= atomic no.
 

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