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Grade: 12
        
The values of electronegativity of atoms A and B are 4 and 1.20 respectively.the percentage ionic character of A-B bond is
14 days ago

Answers : (1)

Arun
16262 Points
							
% ionic character = 16( xA - xB) + 3.5 (xA - xB)^2
Where xA and xB are electronegativities of atom A and B respectively. 
% ionic character = 16( 4-1.2) + 3.5(4-1.2)2
% ionic character = 44.8 + 27.44 = 72.24%
 
14 days ago
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