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The value of k for which the number 3 lies between the roots of equation x^2 + (1 - 2k)x + (k^2 - k - 2) = 0 is given by
A) 2
B) k > 2
C) 2
D) k > 5
[Full Explaination needed]
5 months ago

1807 Points

note that the graph of y= f(x)= x^2 + (1 - 2k)x + (k^2 - k - 2) would be an upward parabola. so, a necessary and sufficient condition for 3 to lie in between roots is f(3) should be less than 0. this is in effect the same as applying intermediate value theorem as  f is continuous.
here, f(3)= 9 + 3(1 –  2k) + k^2 - k - 2 must be less than 0.
or k^2 – 7k + 10 must be less than 0.
or (k – 2)(k – 5) must be less than 0.
so that Ans: k should lie in (2, 5).
your option A and C are wrongly typed so idk what they are.
but D is definitely wrong and B is partially correct.
anways, the ques has been answered.
kindly approve :)
5 months ago
23 Points

Sir, I think there was a problem in placing the options
The Updated Options are
A) 2$<$k$<$5
B) k > 2
C) 2$<$k$<$3
D) k > 5
5 months ago
1807 Points

yeah so obviously option A is correct as it is the same as (2, 5).
if any other doubt, feel free to ask.
kindly approve :)
5 months ago
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• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions