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The question is from the chapter states of matter I have attached the question. please answer the question with complete solution

The question is from the chapter states of matter I have attached the question. please answer the question with complete solution

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Grade:12

1 Answers

Suresh kumar
13 Points
5 years ago
Height of mercury at any angle = height of mercury in vertical column X cos theta
Where theta is angle of mercury with vertical 
 horizontal tube makes angle 90 ° with verical
Tjerfore
h90° = h x cos 90
         = 8 x 0 = 0 cm
P90°= p°+ h90°
        = 76cm + 0cm = 76cm
height of mercury level at angle 45°
h45° = h x cos 45°
          = 8 cm x 1/√2 = 8 x 0.707 cm
          = 5.66 cm
P45° = p° + h45° = 76 + 5.66 cm = 81.66 cm
Acc to Boyles law
P45° V45° = P90° V90°
81.66 x A x length at 45° = 76 x A x length at 90°
81.66 cm x length at 45° = 76 cm  x 12 cm
Length of air at 45° = 76 cm x 12 cm /81.66 cm
                                   = 11.168cm = 11.17 cm
 

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