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Nitin Kumar Grade: 11
        The oxidation number of molybdenum in its oxo complex species [Mo2O4(C2H4)2(H2O2)]^2- is Explain???
one year ago

Answers : (3)

Vikas TU
6872 Points
										
The maxm. CN can be 6.
Here it is 5. Hence oxidation state for Mo would be:
2x +2*-1 + 0 = – 2
x = 0 
Hence it is in 0 state.
one year ago
RAHUL GURJAR
42 Points
										
answer of this question
 
The maxm. CN can be 6.
Here it is 5. Hence oxidation state for Mo would be:
2x +2*-1 + 0 = – 2
x = 0 
Hence it is in 0 state.
4 months ago
Swarnim Gupta
11 Points
										Since C2H4 and H2O2 are neutal molecules so their oxudation state is 0. Therefore [2x + 4(-2) +0+0 = -2]x = 3.
										
4 months ago
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