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the number of silver atoms present in 90% pure silver wire weighing 10g is ---And=5.0×10^22 explain plzzz?????

the number of silver atoms present in 90% pure silver wire weighing 10g is ---And=5.0×10^22 explain plzzz?????

Grade:11

1 Answers

Vikas TU
14149 Points
5 years ago
90% of 10 gm is: 9 gm obvious.
Now moles of silver is: = > 9/108
No. of atoms = (1/12)*Na => 5 x 10^22 atoms.
Where Na is the Avagadro No.

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