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Grade 12Inorganic Chemistry

The equilibrium constant for a reaction is given as Kc = [B] [C] / [A] ². If concentration of A is increased by two times, the new equilibrium constant is
(A) 0.25 Kc
(B) 0.5 Kc
(C) Kc
(D) 2Kc
Please help as the given answer is option C, but I didn't got how the answer came

Profile image of Harish
7 Years agoGrade 12
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1 Answer

Profile image of Arun
ApprovedApproved Tutor Answer7 Years ago
 
Dear student
 
the equation should be 
 
2 A -------> B + C
 
x                  x.    x
 
now
 
if 2x               2x   2x
 
 
if we cakculate Kc in both the cases it will be same

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