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Grade: 12
        
The equilibrium constant for a reaction is given as K= [B] [C] / [A] ². If concentration of A is increased by two times, the new equilibrium constant is
(A) 0.25 Kc
(B) 0.5 Kc
(C) Kc
(D) 2Kc
Please help as the given answer is option C, but I didn't got how the answer came  
6 months ago

Answers : (1)

Arun
21043 Points
							
 
Dear student
 
the equation should be 
 
2 A -------> B + C
 
x                  x.    x
 
now
 
if 2x               2x   2x
 
 
if we cakculate Kc in both the cases it will be same
6 months ago
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