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The equilibrium constant for a reaction is given as K c = [B] [C] / [A] ². If concentration of A is increased by two times, the new equilibrium constant is (A) 0.25 K c (B) 0.5 K c (C) K c (D) 2K c Please help as the given answer is option C, but I didn't got how the answer came

The equilibrium constant for a reaction is given as Kc = [B] [C] / [A] ². If concentration of A is increased by two times, the new equilibrium constant is
(A) 0.25 Kc
(B) 0.5 Kc
(C) Kc
(D) 2Kc
Please help as the given answer is option C, but I didn't got how the answer came  

Grade:12

1 Answers

Arun
25750 Points
5 years ago
 
Dear student
 
the equation should be 
 
2 A -------> B + C
 
x                  x.    x
 
now
 
if 2x               2x   2x
 
 
if we cakculate Kc in both the cases it will be same

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