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The enthalpy of atomisation is very high for Cu but its hydration energy is very low. The high energy to transform Cu to Cu+2 is not balanced by its hydration enthalpy . Thus , for this conversion , E(elecrode potential , M+2 to M)value is positive. question is: Explain : The electrode potential (E M+2/M ) for copper is positive. Copper is only in the first series of transition elements showing their behaviour.

The enthalpy of atomisation is very high for Cu but its hydration energy is very low. The high energy to transform Cu to Cu+2 is not balanced by its hydration enthalpy . Thus , for this conversion , E(elecrode potential ,  M+2 to M)value is positive.
question is: 
Explain :  The  electrode  potential (E M+2/M ) for copper is positive. Copper is only in the first series of transition elements showing their behaviour.
 

Grade:12

1 Answers

Shraddha Singh
273 Points
one month ago
E° (M2+ / M) for any metal is related to the sum of the Enthalpy changes taking place in the following steps:
M(s) + ∆aH → M(g)  {∆aH = Enthalpy of atomisation sublimation}
M(g) + ∆iH → M2+(g)  {∆iH = Ionisation enthalpy} 
M2+(g) + aq. → M2+(aq) + ∆hydH  {∆hydH = hydration enthalpy}
CoppeCopper has high enthalpy of atomisation (i.e. energy absorbed) and low enthalpy of hydration (i.e. energy released). The high energy required to transform Cu(s) to Cu2+(aq) , i.e., sum of enthalpies of sublimation and ionisation is not balanced by its hydration enthalpy. Hence , E°(Cu2+ / Cu) is positive.

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