The bond orders of O22−,O2−,O2 are respectively x, y and z.Then what is the value of 2(x+y+z)?
Shamit Jain , 4 Years ago
Grade 12
Inorganic Chemistry> The bond orders of O 2 2 − , O 2 − , ...
1 Answers
ankit singh
Last Activity: 4 Years ago
ANSWER
The bond orders of O22−,O2−,O2 are respectively x,y and z
Bond order of O2 = 2
Bond order of O2− = 1.5
Bond order of O22− = 1
Here, x=1,y=1.5,z=2
Therefore, the value of 2(x+y+z)=2(1+1.5+2)=9
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