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The atomic numbers of vanadium (V), chromium (Cr), manganese (Mn) and iron (Fe) are respectively 23, 24, 25 and 26. Which one of these may be expected to have the highest second ionisation enthalpy? (1) V (2) Cr (3) Mn (4) Fe

Harshit Singh , 4 Years ago
Grade 12th pass
anser 1 Answers
Pawan Prajapati

Last Activity: 4 Years ago

Answer ::

The second ionisation potential values of Cu and Cr are sufficiently higher than those of neighbouring elements. This is due to the electronic configuration of Cu+ which is 3d10 and of Cr+ which is 3d5.

Hence option (2) is the answer.


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