The ammonia in equilibrium with 1:3 N2-H2 mixture at 20atm and 427 degree celsius amounts to 16%. Calculate Kp and Kc for 1/2 N2 + 1/2 H2 gives NH3.

Question

Vikas TU · Answer

For, 1/2 N2 + 1/2 H2 --------> NH3 at eqm.=> x moles 3x moles 2x moles Now given, (2x) = 0.16 solving for x we get x = 0.08 . Kc = (2x)/root3x => 2/root3 Kp = Kc*(RT)^n n = 1 – (0.5 + 0.5) = 0 Hence Kp = Kc =2/root3.

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The ammonia in equilibrium with 1:3 N2-H2 mixture at 20atm and 427 degree celsius amounts to 16%. Calculate Kp and Kc for 1/2 N2 + 1/2 H2 gives NH3.

The ammonia in equilibrium with 1:3 N2-H2 mixture at 20atm and 427 degree celsius amounts to 16%. Calculate Kp and Kc for 1/2 N2 + 1/2 H2 gives NH3.

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The ammonia in equilibrium with 1:3 N2-H2 mixture at 20atm and 427 degree celsius amounts to 16%. Calculate Kp and Kc for 1/2 N2 + 1/2 H2 gives NH3.

The ammonia in equilibrium with 1:3 N2-H2 mixture at 20atm and 427 degree celsius amounts to 16%. Calculate Kp and Kc for 1/2 N2 + 1/2 H2 gives NH3.

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