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Shape of B F 4 − is: A Tetrahedral B Pyramidal C Trigonal planar D Bent
Boron has 3 valence electrons, and each of the four fluorides contributes one electron to each covalent bond. The overall negative charge of the molecule contributes another electron, so overall we have 3 + 4 + 1 = 8 valence electrons which form 4 electron pairs.The pairs arrange themselves in space to maximise the distance between them, thereby reducing the electronic repulsion between them to a minimum. The shapes for various numbers of electron pairs are:2 - linear3 - trigonal planar4 - tetrahedral5 - trigonal bipyramidal6 - octahedral7 and above - Google!And hence BF4- would be tetrahedral.
Boron has 3 valence electrons, and each of the four fluorides contributes one electron to each covalent bond. The overall negative charge of the molecule contributes another electron, so overall we have 3 + 4 + 1 = 8 valence electrons which form 4 electron pairs.
The pairs arrange themselves in space to maximise the distance between them, thereby reducing the electronic repulsion between them to a minimum. The shapes for various numbers of electron pairs are:
2 - linear3 - trigonal planar4 - tetrahedral5 - trigonal bipyramidal6 - octahedral7 and above - Google!
And hence BF4- would be tetrahedral.
tetrahedralBF4 is the molecular formula of boron tetraflouride. Boron tetraflouride has tetrahedral structure. Boron has 3 valence electrons, and each of the four fluorides involves with one electron to each covalent bond. The overall negative charge of the molecule involves with another electron.
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