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```
rate of first order reaction is 0.04 moles (sec litres)inverse at 10 minutes and 0.003 moles (litres sec) at 20 minutes from start .then calculate half life for reaction
rate of first order reaction is 0.04 moles (sec litres)inverse at 10 minutes and 0.003 moles (litres sec) at 20 minutes from start .then calculate half life for reaction

```
2 years ago

Arun
25768 Points
```							Dear student Reaction type : 1st order reactionFormula used :k =( 2.303/t2-t1) log([R1]/[R2])Given :T1 = 10 min and T2 = 20 min therefore T2-T1 = 10 min[R1] = 0.04 mol/L  and  [R2] = 0.03 mol/LSubstituting the values in the above equationk =( 2.303/10) log( 0.04/0.03)k = 0.2303 [log(0.04) - log (0.03)]k = 0.2303 [-1.3979 - (-1.5228)]k = 0.02876 /minFor the first order reaction half life t1/2 is given byt1/2 = 0.693/kWe know,  k = 0.02876 we gett1/2 = 0.693/0.02876t1/2 = 24.096 min
```
2 years ago
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