badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

rate of first order reaction is 0.04 moles (sec litres)inverse at 10 minutes and 0.003 moles (litres sec) at 20 minutes from start .then calculate half life for reaction

rate of first order reaction is 0.04 moles (sec litres)inverse at 10 minutes and 0.003 moles (litres sec) at 20 minutes from start .then calculate half life for reaction 
 

2 years ago

Answers : (1)

Arun
25768 Points
							
Dear student
 
Reaction type : 1st order reaction

Formula used :

k =( 2.303/t2-t1) log([R1]/[R2])

Given :
T1 = 10 min and T2 = 20 min therefore T2-T1 = 10 min

[R1] = 0.04 mol/L  and  [R2] = 0.03 mol/L

Substituting the values in the above equation

k =( 2.303/10) log( 0.04/0.03)

k = 0.2303 [log(0.04) - log (0.03)]

k = 0.2303 [-1.3979 - (-1.5228)]

k = 0.02876 /min

For the first order reaction half life t1/2 is given by

t1/2 = 0.693/k

We know,  k = 0.02876 we get

t1/2 = 0.693/0.02876

t1/2 = 24.096 min

2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 54 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details