ques1. why does R3P=O exist but R3N=O does not? ques2. SF6 is well known but SH6 is not. why?
sejal , 8 Years ago
Grade 11
Inorganic Chemistry> ques1. why does R3P=O exist but R3N=O doe...
4 Answers
Sanju
Answer to Q#1:
Nitrogen lacks ‘d-orbital’ unlike Phosphorus. The absence of d-orbital restrict nitrogen to expand its co-ordination no beyond 4. Therefore, the structure R3N=O doesn’t exist...
Sanju
Answer to Q#2:
We will start with the hybridization of SF6 first. The hybridization of SF6 is sp3d2.
In order to form SH6, the hybridization state should be same as that of SF6. Since d-orbitals are very high energy orbital, sp3d2 is possible with only with high electronegative elements like Fluorine. So the electronegativity value of Hydrogen is inadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation of sp3d2 hybridized orbital.
Ravleen Kaur
Hello Student,
Due to the absence of d-orbital in nitrogen which belongs to second period (d-orbital availibility starts from third period onwards)R3N=O does not.
Since d-orbitals have high energy ,sp3d2is possible only with high electronegative elements likeFluorine which makes the d-orbital closer in energy to s and p orbital so that they can hybridise easily and effeciently. The electronegativity value of Hydrogen isinadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation ofsp3d2. That is why SF6 is well known but SH6 is not.
All the Best
Regards
Ravleen Kaur
Due to the absence of d-orbital in nitrogen which belongs to second period (d-orbital availibility starts from third period onwards)R3N=O does not.
Since d-orbitals have high energy ,sp3d2is possible only with high electronegative elements likeFluorine which makes the d-orbital closer in energy to s and p orbital so that they can hybridise easily and effeciently. The electronegativity value of Hydrogen isinadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation ofsp3d2. That is why SF6 is well known but SH6 is not.
All the Best
Regards
Ravleen Kaur
Rishi Sharma
Dear Student,
Please find below the solution to your problem.
Due to the absence of d-orbital in nitrogen which belongs to second period (d-orbital availibility starts from third period onwards)R3N=O does not. Since d-orbitals have high energy , sp3d2 is possible only with high electronegative elements likeFluorine which makes the d-orbital closer in energy to s and p orbital so that they can hybridise easily and effeciently. The electronegativity value of Hydrogen isinadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation of sp3d2. That is why SF6 is well known but SH6 is not.
Thanks and Regards
Please find below the solution to your problem.
Due to the absence of d-orbital in nitrogen which belongs to second period (d-orbital availibility starts from third period onwards)R3N=O does not. Since d-orbitals have high energy , sp3d2 is possible only with high electronegative elements likeFluorine which makes the d-orbital closer in energy to s and p orbital so that they can hybridise easily and effeciently. The electronegativity value of Hydrogen isinadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation of sp3d2. That is why SF6 is well known but SH6 is not.
Thanks and Regards
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