Inorganic Chemistry> ques1. why does R3P=O exist but R3N=O doe...

ques1. whydoesR3P=OexistbutR3N=Odoesnot?ques2. SF6iswellknownbutSH6 is not. why?

sejal , 6 Years ago

Grade 11

4 Answers

Sanju

Last Activity: 6 Years ago

Answer to Q#1:

Nitrogen lacks ‘d-orbital’ unlike Phosphorus. The absence of d-orbital restrict nitrogen to expand its co-ordination no beyond 4. Therefore, the structure R₃N=O doesn’t exist...

Sanju

Last Activity: 6 Years ago

Answer to Q#2:

We will start with the hybridization of SF₆ first. The hybridization of SF₆is sp³d².

In order to form SH₆, the hybridization state should be same as that of SF₆. Since d-orbitals are very high energy orbital, sp³d²is possible with only with high electronegative elements like Fluorine. So the electronegativity value of Hydrogen is inadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation of sp³d²hybridized orbital.

Ravleen Kaur

Last Activity: 6 Years ago

Hello Student,

Due to the absence of d-orbital in nitrogen which belongs to second period (d-orbital availibility starts from third period onwards)R3N=O does not.

Since d-orbitals have high energy ,sp3d2is possible only with high electronegative elements likeFluorine which makes the d-orbital closer in energy to s and p orbital so that they can hybridise easily and effeciently. The electronegativity value of Hydrogen isinadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation ofsp3d2. That is why SF6 is well known but SH6 is not.

All the Best
Regards
Ravleen Kaur

Rishi Sharma

Last Activity: 4 Years ago

Dear Student,
Please find below the solution to your problem.

Due to the absence of d-orbital in nitrogen which belongs to second period (d-orbital availibility starts from third period onwards)R3N=O does not. Since d-orbitals have high energy , sp3d2 is possible only with high electronegative elements likeFluorine which makes the d-orbital closer in energy to s and p orbital so that they can hybridise easily and effeciently. The electronegativity value of Hydrogen isinadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation of sp3d2. That is why SF6 is well known but SH6 is not.
Thanks and Regards