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Grade: 11
        ques1. why  does  R3P=O  exist  but  R3N=O   does  not?     ques2. SF6  is  well  known  but  SH6 is not. why?
2 years ago

Answers : (4)

Sanju
106 Points
							
Answer to Q#1:
Nitrogen lacks ‘d-orbital’ unlike Phosphorus. The absence of d-orbital restrict nitrogen to expand its co-ordination no beyond 4. Therefore, the structure R3N=O doesn’t exist...
 
2 years ago
Sanju
106 Points
							
Answer to Q#2:
We will start with the hybridization of SF6 first. The hybridization of SFis sp3d2.
In order to form SH6, the hybridization state should be same as that of SF6. Since d-orbitals are very high energy orbital, sp3dis possible with only with high electronegative elements like Fluorine. So the electronegativity value of Hydrogen is inadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation of sp3dhybridized orbital.
2 years ago
Ravleen Kaur
askIITians Faculty
1451 Points
							Hello Student,

Due to the absence of d-orbital in nitrogen which belongs to second period (d-orbital availibility starts from third period onwards)R3N=O does not.

Since d-orbitals have high energy ,sp3d2is possible only with high electronegative elements likeFluorine which makes the d-orbital closer in energy to s and p orbital so that they can hybridise easily and effeciently. The electronegativity value of Hydrogen isinadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation ofsp3d2. That is why SF6 is well known but SH6 is not.

All the Best
Regards
Ravleen Kaur
2 years ago
Rishi Sharma
askIITians Faculty
614 Points
							Dear Student,
Please find below the solution to your problem.

Due to the absence of d-orbital in nitrogen which belongs to second period (d-orbital availibility starts from third period onwards)R3N=O does not. Since d-orbitals have high energy , sp3d2 is possible only with high electronegative elements likeFluorine which makes the d-orbital closer in energy to s and p orbital so that they can hybridise easily and effeciently. The electronegativity value of Hydrogen isinadequate to bring the energy of d orbitals equivalent to the energy of p orbitals,which is necessery for the formation of sp3d2. That is why SF6 is well known but SH6 is not.
Thanks and Regards

one month ago
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