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Ques: The strength of bonds by 2s-2s , 2p-2p , 2p-2s overlap has order (1) s-s>s-p>p-p (2) p-p >s-p >s-s Explain with reason ?

Ques: The strength of bonds by 2s-2s , 2p-2p , 2p-2s overlap has order 
(1) s-s>s-p>p-p 
(2) p-p >s-p >s-s 
Explain with reason ?

Grade:12th pass

5 Answers

Umakant biswal
5349 Points
7 years ago
@ diksha 
acc to the question , option no 1 that is s-s>s-p>p-p turns out to be the correct answer . 
as u knows s-s is head on head overlapping and hence , its the strongest . and the 2nd strongest is s-p due to intermixing of overlapping .. 
and the least strong is p-p due to axial overlapping .. 
HOPE IT CLEARS YOUR DOUBT 
IF ANY MORE , THEN LET ME KNOW 
ALL THE BEST ..
 
Saurav
11 Points
6 years ago
Second option is correct.On the basis of extent of overlapping, greater the area of overlapping greater is the strength of bond.Since the area of overlapping is greatest in case of p-p bond due to its dumbbell shape, so it has greatest strength followed by s-p and then s-s.
Javid Ahmad dar
15 Points
4 years ago
The extent of overlapping depends on principl quantum number ,,,1s-1s,will show much extent than 2p_2p,which show much than 2s_2p
Aashish Sharma
15 Points
3 years ago
It depends if we talk about size then s-s is smaller in size hence the distance of nucleus is small from electron hence s-s bond is stronger than s-p and p-p 
If we talk about direction then p-p overlapping is directional and s-s overlapping is non directional si p-p overlapping is strong 
 
One more factor that is area p orbital have more area than s orbital hence there will be extent overlapping so p-p overlapping is strong
 
preet3shukla
7 Points
one year ago
It depend on the extent of overlapping as p-p has more extent of overlapping.It doesnot has any affect of IND(internuclear distance ) imfact all pp ss and sp have same IND.
 

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