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​Q . IF THE DIPOLE MOMENT OF OH- BOND IN WATER IS 1.5 D AND THE BOND ANGLE H-O-H IS 104 0 20 ’ . CALCULATE THE DIPOLE MOMENT OF WATER MOLECULE( COS 104 0 20 ’ = -0.2476).

​Q . IF THE DIPOLE MOMENT OF OH-
BOND IN WATER IS 1.5 D AND THE BOND ANGLE  H-O-H IS 1040 20’ . CALCULATE THE DIPOLE MOMENT OF WATER MOLECULE( COS 1040 20’ = -0.2476).

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2 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
The bond angle between two OH=104deg20min
The resulatant dipole moment is avector quantity
H2o is a molecule having two OH bond in a molecule.Thus the resultant dipole moment is sqrt (u1^2 +u2^2+2u1u2cos104^020)
sqrt(3.31)
=1.82D
Thus the dipole moment of water is 1.8D
Px dragon
13 Points
3 years ago
U(mew of compound) =2*diplemovement *cos (104.5/2)   
                                         =2*1.5*0.6123 
                                          =1.85 
Thank you asfghjh100 char needed to post

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