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PURE o2 diffuses through an aperture in 224 seconds,whereas mixture of o2 and anther gas containing 80% o2 diffuses from the same in 234 sec .what is the molecular weight of gas?

PURE o2 diffuses through an aperture in 224 seconds,whereas mixture of o2 and anther gas containing 80% o2 diffuses from the same in 234 sec .what is the molecular weight of gas?

Grade:11

1 Answers

Arun
25750 Points
5 years ago

For gaseous mixture 80% O2, 20% of other gas m   

Average molecular weight Mm = 32 (for O2) × 80 + 20 × m / 100   

Now, for diffusion of gaseous mixture and pure O2   

rO2 / rm = √Mm / MO2 or VO2 / EO2 × Em / Vm = √Mm / MO2   

∴ 1 / 224 × 234 / 1 = √Mm / 32 

∴ Mm= 34.92  

∴ 32 × 80 + 20 × m / 100 = 34.92   

∴ m = 46.6

 

Regards

Arun

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