MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
PURE o2 diffuses through an aperture in 224 seconds,whereas mixture of o2 and anther gas containing 80% o2 diffuses from the same in 234 sec .what is the molecular weight of gas?
21 days ago

Answers : (1)

Arun
16262 Points
							

For gaseous mixture 80% O2, 20% of other gas m   

Average molecular weight Mm = 32 (for O2) × 80 + 20 × m / 100   

Now, for diffusion of gaseous mixture and pure O2   

rO2 / rm = √Mm / MO2 or VO2 / EO2 × Em / Vm = √Mm / MO2   

∴ 1 / 224 × 234 / 1 = √Mm / 32 

∴ Mm= 34.92  

∴ 32 × 80 + 20 × m / 100 = 34.92   

∴ m = 46.6

 

Regards

Arun

21 days ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 54 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 148 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details