Grade 12th passInorganic Chemistry
Please explain the answer of the above ionic equilibrium question.how to solve these types of question?
1 Answer
Arun
Mass of the Sodium Hydroxide = 0.15 g
Molar Mass of the Sodium Hydroxide = 40 g/mole.
[∵ 23 + 16 + 1 = 40]
∵ No. of moles = Mass/Molar Mass
∴ No. of moles = 0.16/40
⇒ No. of moles of Sodium Hydroxide = 0.004 moles.
= 0.004× 10³ millimoles [ ∵ 1 mole = 10³ millimoles.]
= 4 millimoles.
Hence, the number of millimoles in the 0.16 grams of the Sodium hydroxide is 4 millimoles.
Hope it helps
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