Inorganic Chemistry> PbI 4 does not exist because...

PbI₄ does not exist because

Gman Namg , 10 Years ago

Grade 12

5 Answers

Komal

The Iodide reduces the lead to Pb(II) and the Pb oxidizes the Iodide to Iodine (I2). Since iodide is not a strong enough reducing agent to reduce Pb(II) to Pb, the ionic compoundPbI2 is formed. Pb4+ , being a strong acid (strong oxidant) will take up electrons from soft base (have fairly good reducing power) I- to oxidise it to I2 and it self will reduce to Pb2+ to form PbI2

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Last Activity: 10 Years ago

grenade

bigger size of iodine cause of the reducing nature of the iodine

thus it would reduce lead to form the compound PbI2

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Last Activity: 10 Years ago

Abesh Bhar

Here in PbI₄, Pb has +4 oxidation state. Now the electronic configuration of Pb is [Xe]4f¹⁴5d¹⁰6s²6p². So we can see that there is 14 f electrons which have very poor shielding effect. So the effective nuclear charge on the outer s & p electrons are increased. So they are stongly attracted towards nucleus and hence becomes inert. So the Pb⁴⁺ becomes unstable and shows stong oxidising property. So it reduced to Pb²⁺. On the other hand, I^- shows high reducing property. So the association of these two ions are quite impossible. Hence PbI₄ does not exist.

Last Activity: 8 Years ago

Aswin Sankar PD

PbI4 does not exist because, During the formatio of Pb-I enough amount of energy is not released so as to unpair one of the 6s^2 electron and excite one of them to higher orbital to have a lone electron around the central atom.

Last Activity: 8 Years ago

Thomas

PbI4 does not exist because pb-I bond initially formed during the reaction does not release enough energy to unpair 6S² electron and excite 1 electron around pb Central atom

Last Activity: 6 Years ago