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Nitin Kumar Grade: 11
        Oxidation number of sulphur in (NH4)2S2O8 is Explain?????????!?????????????!!
one year ago

Answers : (1)

Akilesh Kannan
24 Points
										
+6. If u go by the normal way of calculating oxidation state, u will get 7, which is not possible as S can lose a max. of 6 electrons(the ones in its outer shell). But, if u draw the structure, u will get the correct answer. I dont know how to draw the structure over here, sorry!
one year ago
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