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Oxidation number of sulphur in (NH4)2S2O8 is Explain?????????!?????????????!!

Oxidation number of sulphur in (NH4)2S2O8 is Explain?????????!?????????????!!

Grade:11

1 Answers

Akilesh Kannan
24 Points
7 years ago
+6. If u go by the normal way of calculating oxidation state, u will get 7, which is not possible as S can lose a max. of 6 electrons(the ones in its outer shell). But, if u draw the structure, u will get the correct answer. I dont know how to draw the structure over here, sorry!

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