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oxidation no. of boron in NaBH4 Also, can u explain it through structure

oxidation no. of boron in NaBH4
Also, can u explain it through structure
 

Grade:10

1 Answers

Arun
25750 Points
6 years ago
Let the oxidation state of Boron be X
As the oxidation state of Na is +1 and Hydrogen is -1 because here hydrogen exist as hydride.
Therefore
X + (+1) + 4(-1) = 0
X = +3
Hence the oxidation state of boron is +3.

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