Odd electron bond is present in Ko2Na2o2Bao2Pcl6-
Odd electron bond is present in
Ko2
Na2o2
Bao2
Pcl6-
Aditi , 5 Years ago
Grade 11
Inorganic Chemistry> Odd electron bond is present in Ko2 Na2o2...
2 Answers
ROSHAN MUJEEB
Last Activity: 5 Years ago
Generally, the elements possess odd number of electrons will have unpaired electrons.
So, forKO2there would be 35 electrons(19+8×2)
ForAlO2−there would be 20 electrons(13+8×2+1)(for negative charge)
ForBaO2there would be 72 electrons(56+16)
ForNO2+there would be 12 electrons(7+8×2−1)(for positive charge)
So onlyKO2is having odd number of electrons so it is having unpaired electrons.
KO2has(K++O2−)structure having one unpaired electron due to presence of superoxide ion(O2−ion)in it, which is paramagnetic.
Hence option A is correct.
So, forKO2there would be 35 electrons(19+8×2)
ForAlO2−there would be 20 electrons(13+8×2+1)(for negative charge)
ForBaO2there would be 72 electrons(56+16)
ForNO2+there would be 12 electrons(7+8×2−1)(for positive charge)
So onlyKO2is having odd number of electrons so it is having unpaired electrons.
KO2has(K++O2−)structure having one unpaired electron due to presence of superoxide ion(O2−ion)in it, which is paramagnetic.
Hence option A is correct.
ajay
Last Activity: 4 Years ago
Generally, the elements possess odd number of electrons will have unpaired electrons.
So, forKO2there would be 35 electrons(19+8×2)
ForAlO2−there would be 20 electrons(13+8×2+1)(for negative charge)
ForBaO2there would be 72 electrons(56+16)
ForNO2+there would be 12 electrons(7+8×2−1)(for positive charge)
So onlyKO2is having odd number of electrons so it is having unpaired electrons.
KO2has(K++O2−)structure having one unpaired electron due to presence of superoxide ion(O2−ion)in it, which is paramagnetic.
Hence option A is correct.
So, forKO2there would be 35 electrons(19+8×2)
ForAlO2−there would be 20 electrons(13+8×2+1)(for negative charge)
ForBaO2there would be 72 electrons(56+16)
ForNO2+there would be 12 electrons(7+8×2−1)(for positive charge)
So onlyKO2is having odd number of electrons so it is having unpaired electrons.
KO2has(K++O2−)structure having one unpaired electron due to presence of superoxide ion(O2−ion)in it, which is paramagnetic.
Hence option A is correct.
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