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Number of moles of K2Cr2O7 reduced by one mole of iodide ions is

Number of moles of K2Cr2O7 reduced by one mole of iodide ions is

Grade:12

1 Answers

Arun
25750 Points
6 years ago
Dear student
Cr2O72– + 6 I + 14 H+ -----------> 2 Cr3+  + 3 I2 + 7 H2O
hence
Number of moles of K2Cr2O7 reduced by one mole of iodide ions is = 1/6
Regards
Arun (askIITians forum expert)

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