Grade 12Inorganic Chemistry
Molal enthalpy of fusion of water at 273K is 6KJ\mol calculated value of molal depression constant for water.
1 Answer
Beenu Mathew
Hi,
there is an formula to solve this question:-
Kf=R*Ma* (T0f)2/1000*∆Hfus
Ma= mass of solvent(here water)
T0f= melting point temperature (here 273K)
∆Hfus= enthalpy of fusion
just plug in these values and you will get
Kf= 1.858 K.kg/mol
CHEERS!!
HOPE THIS HELPS!!
GOOD LUCK!!
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