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m1v1/n1=m2v2/n2 m1=molarity of Na2Co3 =0.2836 v1=volume of Na2Co3 = 20ml n1=number of moles of HCL =1 m2=molarity of HCL=? v2=volume of HCL =19.6 n2=number of moles of hcl =2 please calculate this

m1v1/n1=m2v2/n2
 
m1=molarity of Na2Co3 =0.2836
v1=volume of Na2Co3 = 20ml
n1=number of moles of HCL =1
m2=molarity of HCL=?
v2=volume of HCL =19.6
n2=number of moles of hcl =2
 
please calculate this

Grade:12th pass

2 Answers

Umakant biswal
5359 Points
6 years ago
@ navin 
This is an easy ques , all the value are mentioned in the question the only thing is u have to substitute that correctly , for the term m2 
acc to the question 
m1v1/n1= m2v2/n2 
so, by calculating 
m1v1n2 = m2v2n1 
or m2v2n1 = m1v1n2
so, by  arrenging the equation 
m2 = m1v1n2 / v2n1 
now substitute the value and get the answer 
here the answer will be 0.57 
HOPE IT CLEARS YOUR DOUBT 
koo
15 Points
3 years ago
It is wrong, how the no. of moles of Na2CO3 could be 1?, please use the values as per the balance chemical equation.
 

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