Lithium forms body centerd cubic structure.The length of the side of its unit cell is 351 pm.atomic radius of lithium will be (a)300pm(b)240pm(c)152pm(d)75pm

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Vikas TU · Answer

In BCC lattice, the relation b.w the radii of atoma nd the length of the cell would be=> root(3)*a/2 = 2r radius => root(3)*a/4 => 351*root(3)/4 = 151.8 pm that is approximately 152 pm.

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Lithium forms body centerd cubic structure.The length of the side of its unit cell is 351 pm.atomic radius of lithium will be (a)300pm(b)240pm(c)152pm(d)75pm

Lithium forms body centerd cubic structure.The length of the side of its unit cell is 351 pm.atomic radius of lithium will be (a)300pm(b)240pm(c)152pm(d)75pm

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Lithium forms body centerd cubic structure.The length of the side of its unit cell is 351 pm.atomic radius of lithium will be (a)300pm(b)240pm(c)152pm(d)75pm

Lithium forms body centerd cubic structure.The length of the side of its unit cell is 351 pm.atomic radius of lithium will be (a)300pm(b)240pm(c)152pm(d)75pm

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