KIO 3 +5KI +6HCl − 3I 2 +6KCl +3H 2 O 1. I - is r

Question

KIO3 +5KI +6HCl −> 3I2 +6KCl +3H2O 1. I- is reduced to I2​ 2. IO3- is oxidised to I2 3. IO3- is reduced to I2 4. Oxidation number of I increases from -1 [KI] to 0 [I2]. the correct statements are (1) 1,2,4 (2) 3,4 (3) 1,4 (4) 1,3,4

Jatin Punera · Accepted Answer

3,4 as the 1st option can never be correct because I – can never be reduced to Iodine it will be oxidised as the oxidation state of Iodine is zero.so that leaves us with only the 4th option this was a shortcut way but if you solve them Iodate has Iodide in +5 oxidation state so it will be reduced to Iodine which is correct then in KI Iodide is in -1 state which is absolutely correct and then it forms Iodine gas where oxidation state is 0 and thus correct.:)

Inorganic Chemistry> KIO 3 +5KI +6HCl −> 3I 2 +6KCl +3H 2 O 1....

KIO₃+5KI +6HCl −> 3I₂ +6KCl +3H₂O 1. I^-is reduced to I₂ 2. IO₃^- is oxidised to I₂3. IO₃^-is reduced to I₂ 4. Oxidation number of I increases from -1 [KI] to 0 [I₂]. the correct statements are (1) 1,2,4 (2) 3,4 (3) 1,4 (4) 1,3,4

mansheeth , 10 Years ago

Jatin Punera

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Inorganic Chemistry> KIO 3 +5KI +6HCl −> 3I 2 +6KCl +3H 2 O 1....

KIO3 +5KI +6HCl −> 3I2 +6KCl +3H2O 1. I- is reduced to I2​ 2. IO3- is oxidised to I2 3. IO3- is reduced to I2 4. Oxidation number of I increases from -1 [KI] to 0 [I2]. the correct statements are (1) 1,2,4 (2) 3,4 (3) 1,4 (4) 1,3,4

mansheeth , 10 Years ago

Jatin Punera

LIVE ONLINE CLASSES

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KIO₃+5KI +6HCl −> 3I₂ +6KCl +3H₂O 1. I^-is reduced to I₂ 2. IO₃^- is oxidised to I₂3. IO₃^-is reduced to I₂ 4. Oxidation number of I increases from -1 [KI] to 0 [I₂]. the correct statements are (1) 1,2,4 (2) 3,4 (3) 1,4 (4) 1,3,4

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