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Grade: 11
        
kindly tell que 19...... density of o2......fast plxxx
3 months ago

Answers : (1)

Arun
23036 Points
							
the density of molecules of gas : 

ρ = P * M/R * T 

a) at STP ( P = 1.01 * 10^5 Pa T = 273 K) 
M O2 = 32 g/mole = 0.032 kg/mole 
ρ = P * M/R * T 
= (1.01 * 10^5 * 0.032)/(8.31 * 273 ) 
= 1.425 kg/m^3 

b) at P = 2 atm = 273 K 
ρ = P * M/R * T 
= (2 * 1.01 * 10^5 * 0.032)/(8.31 * 273 ) 
=2.849 kg/m^3 

c) ρ = P * M/R * T 
= (4 * 1.01 * 10^5 * 0.032)/(8.31 * 546 ) 
= 2.848 kg/m^3 

d) ρ = P * M/R * T 
= (3 * 1.01 * 10^5 * 0.032)/(8.31 * 546 ) 
=2.136 kg/m^3
 
Hence option A is correct
3 months ago
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