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KCl + CO2 + NH3 + H2O gives KHCO3 + NH4Cl
i.e., pottassium bicarbonate is too soluble to be precipitated by the addition of ammonium bicarbonate to a saturated solution of pottasium chloride
Hence K2CO3 cannot be prepared by Solvay Processs.
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Arun (askIITians forum expert)
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