varun
Last Activity: 8 Years ago
Hello,
Be2+ is the right answer
because see the below explanation below
The hydration enthalpies of alkali metal ion decreases with increase in ionic sizes
So, the order is Li+>Na+>K+>Rb+>Cs
So hydration enthalpy for Li+ is more
But Be2+ is also there right
So ionic size for Li+>Be2+
so the size of Be2+ is less so hydration energy for Be2+ is more than Li+
AND WE HAVE ALSO OTHER METGOD TO SOLVE THIS PROBLEM ie
small the size of ion the greater the hydration energy
so BE2+ IS THE ANSWER
please approve me if the answer is correct
THANK YOU