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Ionic radii of a. Ti4+ b. 35CI – c. K+ > CI – d. P3+ > P5+

Ionic radii of
a. Ti4+ < Mn7+
b. 35CI – < 37CI –
c. K+ > CI –
d. P3+ > P5+

Grade:10

1 Answers

Kevin Nash
askIITians Faculty 332 Points
9 years ago
Sol. (a) Ti4+ > Min7+ is the correct order of size due to lower positive charge on Ti4+. (b) 37CI– = 37CI– : Isotopes with same charge have same size because isotopes differ in compositions of nuclei which do not affect the atomic/ionic radius. (c) K+ <$1$2> P5+ is the correct order. For the same elements, lower the positive charge, larger the ions.

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