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In an experiment at 1000 kelvin, the concentration of different species are:•[NH3]= 0.105 mol/dm^3•[N2]= 1.10 mol/dm^3•[H2]= 1.50 mol/dm^3Then calculate KC and KP for the reaction: N2+3H2⇌2NH3Could you please explain with easy steps.

In an experiment at 1000 kelvin, the concentration of different species are:•[NH3]= 0.105 mol/dm^3•[N2]= 1.10 mol/dm^3•[H2]= 1.50 mol/dm^3Then calculate KC and KP for the reaction: N2+3H2⇌2NH3Could you please explain with easy steps.

Grade:11

1 Answers

Chhavi Jain
92 Points
6 years ago
Dear student, 
 
              N2(g)           +          3 H2(g)  ------>   2NH3(g)
 
conc.   1.10 mol L-1        1.50 mol L-1           0.105 mol L-1
 
Kc  = [ NH3 ] 2  /    [N2] [ H2]3
Now put the values of conc. ; we will get the values of Kc --->
Kc =  2.96 * 10-3   mol L-1
 
Now to calculate Kuse the formula :
 
K = Kc ( RT )Δn
 
where , Δn = 2- ( 3+1 ) = -2
 
Place the values  and find Kp
 
Chemistry Consultant
Askiitians
 

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