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If the radius of first Bohr orbit is x then the radius of the third orbit would be. (a)3*x(b)6*x(c)9*x(d)1/9*x
R =0.529n^2/z. For given part n=1 and r=x. And for 3rd orbit n will be 3 and put in the above equation r = 9 times the radius of given and the given r =x then the result of answer is 9x
The radius of n th Bohr orbit is given by Rn = 0.53 ×n^2/zHence here 0.53 means x. ,Therefore, x × 9( since n=3 and z=1 )9x is the answer.
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