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If one mole of sulphite ion accepts 24.08×10^23 electon the possible product is -(1)SO4^2-(2)S^2-(3)S(4)S2O3^2-explain???

Nitin Kumar , 7 Years ago
Grade 11
anser 1 Answers
GAGANDEEP SINGH

Last Activity: 7 Years ago

In this 4 electrons are accepted by the sulphite ion. So a drop of 4 units in oxidation state of S should take place I.e., +2 -> -2. So answer is (2).

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