If one mole of sulphite ion accepts 24.08×10^23 electon the possible product is -(1)SO4^2- (2)S^2- (3)S (4)S2O3^2- explain???

Question

GAGANDEEP SINGH · Answer

In this 4 electrons are accepted by the sulphite ion. So a drop of 4 units in oxidation state of S should take place I.e., +2 -> -2. So answer is (2).

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If one mole of sulphite ion accepts 24.08×10^23 electon the possible product is -(1)SO4^2- (2)S^2- (3)S (4)S2O3^2- explain???

If one mole of sulphite ion accepts 24.08×10^23 electon the possible product is -(1)SO4^2- (2)S^2- (3)S (4)S2O3^2- explain???

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If one mole of sulphite ion accepts 24.08×10^23 electon the possible product is -(1)SO4^2- (2)S^2- (3)S (4)S2O3^2- explain???

If one mole of sulphite ion accepts 24.08×10^23 electon the possible product is -(1)SO4^2- (2)S^2- (3)S (4)S2O3^2- explain???

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