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`        If logxlog18 (Sq.rt 2 + Sq.rt 8) = 1/3. Then what is the value of 1000x?`
9 months ago

Arun
23760 Points
```							logx (log18(√2+√8)) = 1/3 x1/3 = log18(√2+√8) x1/3 = log18(3√2)      √18 = √9√2 = 3√2 So, x1/3 = log18(18)1/2       x1/3 = 1/2       (x1/3)3 = (1/2)3            x = 1/8. So, 1000x = 125.
```
9 months ago
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• 54 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions