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If an element A shows two cationic states +2 and +3 and form oxides in such a way that ratio of the element showing +2 and +3 state is 1:3 in a compound. Formula of the compound will be?

If an element A shows two cationic states +2  and +3 and form oxides in such a way that ratio of the element showing +2 and +3 state is 1:3 in a compound. Formula of the compound will be?

Grade:11

1 Answers

Arun
25750 Points
4 years ago
 

let no of atoms in +2 is x

so, no of atoms in +3 is 3x

hence, charge on atom A is  2x +3[3x] = 11x

SO, NET CHARGE ON OXYGEN IS 11x

let no of oxygen atoms be y

charge on one oxygen atom is 2

2y = 11x

so, y=11x/2

 

hence compound is AxA3x[O11X/2]

i.e A4x[O11x/2]

i.eA8x[O11x]

i.eA8O11 

 

Regards

Arun (askIITians forum expert)

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