If λ 0 is the threshold wavelength for photoelectric emission, λ is the wavelength of light falling on the surface of metal and m is the mass of electron, then find the de Broglie wavelength of emitted electron.

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Vikas TU · Answer

λ =h/mv Where λ= wavelength of electron, h= planck's consistent m=mass of the electron v= speed of the electron however, v= λ0*1/T where T= time period.

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If λ 0 is the threshold wavelength for photoelectric emission, λ is the wavelength of light falling on the surface of metal and m is the mass of electron, then find the de Broglie wavelength of emitted electron.

If λ₀ is the threshold wavelength for photoelectric emission, λ is the wavelength of light falling on the surface of metal and m is the mass of electron, then find the de Broglie wavelength of emitted electron.

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If λ 0 is the threshold wavelength for photoelectric emission, λ is the wavelength of light falling on the surface of metal and m is the mass of electron, then find the de Broglie wavelength of emitted electron.

If λ0 is the threshold wavelength for photoelectric emission, λ is the wavelength of light falling on the surface of metal and m is the mass of electron, then find the de Broglie wavelength of emitted electron.

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If λ₀ is the threshold wavelength for photoelectric emission, λ is the wavelength of light falling on the surface of metal and m is the mass of electron, then find the de Broglie wavelength of emitted electron.