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I in case of CF3I has a partial charge of +1 and in case of CH3I has a partial charge of -1. Why? I know it is related to electronegativity but please explain!

I in case of CF3I has a partial charge of +1 
and in case of CH3I has a partial charge of -1.
Why?
I know it is related to electronegativity but please explain!

Grade:

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
7 years ago
IN case of CF3I it dissociates as CF3- and I+ the charge on iodine is +1 whereas CH3I dissociates as CH3+ and I- the charge in case of I- is -1.see as the electronegativity of flourine is the highest therefore CF3- is formed and in case of CH3I hydrogen electronegativity is less than iodine therefore it forms as CH3+ and I-

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