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hOw to calculate the number Of nuetrons present in 9mg of O18 ..please give proper answer

hOw to calculate the number Of nuetrons present in 9mg of O18 ..please give proper answer

Grade:12

1 Answers

Mohd Mujtaba
131 Points
4 years ago
Here no of neutron in one atom of 18O=18-8=10.Therefore no of neutron in 18 g of 18O=10×Na.So no of neutron in 9mg of O18=(10×Na×9×10^-3)÷18=3×10^21 So answer is 3×10^21

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