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How to calculate the number of neutrons present in 9mg of O18 isotope??

How to calculate the number of neutrons present in 9mg of O18 isotope??

Grade:12

1 Answers

varun
304 Points
6 years ago
HELLO AARTI,
Number of neutron in one O atom = 18-8
                                                            =  10
Now,
mole of oxygen atoms = 9 X 10^-3/18
 So atoms of oxygen = moles X 6.023 X 10^23
So neutons = no of atoms X 10
                    =     3 X 10^21 neutrons
THANK YOU

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