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How much will the kinetic energy and total energy of an electron in H atom change if the atom emits a photon of wavelength 4860 angstrom unit?

Aryan Kumar , 6 Years ago
Grade 11
anser 1 Answers
Eshan

Last Activity: 6 Years ago

Dear student,

The energy lost by atom in emiting photon of given wavelenght=\dfrac{hc}{\lambda}=2.55eV
Hence the electron must be in the fourth shell with total energy of -0.85eV and kinetic energy of 0.85eV and finally dropped to the second shell with energy -3.4eV and kinetic energy 3.4eV to release photon with energy equal to --0.85eV-(-3.4eV)=2.55eV

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