Vikas TU
Last Activity: 8 Years ago
2KClO3 ==> 2KCl + 3O2
You require what number of mols O2? That is
n = PV/RT. Substitute and tackle for n = mols O2.'
At ntp , p = 1 atm , t = 293 k ,
R = 259.8 for oxygen
2 = 1 x v/293 x 259.8 =
2 = v/76,121.4
V= 76,121.4 x 2
152.8 l
1 Mole of oxygen has 24 volume
X mole has 152.8 , x = 24/152.8 = 0.157 moles of oxygen .